As we all know , we can draw a 3-dimensional 0bject in a 2-dimensional blackbold.
so the question is as follow:
why can't we draw a 4-dimensional object in 3-dimensional space?
Nikoidcuexfhtdjxou sglqsmrnyvn
hi there
1-dimension: x=r, r can be minus
2-dimension: x=r cosα, y=r sinα, r could be, but needn't be, minus
3- dimension: x=r cosα sinθ, y=r sinα sinθ, z=r cosθ
4-dimension: x=r cosα sinθ sinλ, y=r sinα sinθ sinλ, z=r cosθ sinλ, i=r cosλ
...
以投影面为坐标面,如果只是投影,则只需把最后一维去掉即可;如果要算累积,那就积分。
3维到2维,投影面为xy平面,去掉z轴
2维到1维,投影面为x直线,去掉y轴
4维到3维,投影面为xyz体,去掉i轴
……
well, that's what projection does,right?
and since you already have 2-D projection, the simplest way is to just add the additional dimension and problem solved.
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Hello
Nikoidcuexfhtdjxou sglqsmrnyvn
Hello
hi there
geometry and algebra
1-dimension: x=r, r can be minus
2-dimension: x=r cosα, y=r sinα, r could be, but needn't be, minus
3- dimension: x=r cosα sinθ, y=r sinα sinθ, z=r cosθ
4-dimension: x=r cosα sinθ sinλ, y=r sinα sinθ sinλ, z=r cosθ sinλ, i=r cosλ
...
以投影面为坐标面,如果只是投影,则只需把最后一维去掉即可;如果要算累积,那就积分。
3维到2维,投影面为xy平面,去掉z轴
2维到1维,投影面为x直线,去掉y轴
4维到3维,投影面为xyz体,去掉i轴
……
well, that's what projection
well, that's what projection does,right?
and since you already have 2-D projection, the simplest way is to just add the additional dimension and problem solved.